maths

jass:

(4x+3)(4x-3)

Hi Jass,
you can do it like this

it might be easier to remember if you think of it like this
You have (4x+3) lots of (4x-3) so therefore you must have 4 lots of BLUE BRACKET + 3 lots of BLUE BRACKET
(4x+3)(4x-3) = 4x(4x-3) +3(4x-3) and than expand the brackets separately, then collect like terms,then you are finished

OR

You might recognise this as a difference of 2 squares
The terms inside the brackets are the same only one has a + in the middle and the other has a - in the middle.
A difference of 2 squares question expands like this:
(a+b)(a-b) = a ² - b ²
You can do this on your example.

if you have problems or questions then repost.