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A=1/2bh

 Aug 18, 2016
 #1
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ok So you want to make b the subject of the equation  :))

 

\(A=\frac{1}{2}bh\\ \)

 

To get b on its own you have to get rid of the 1/2 and the h on the right hand side.

To do you do that??

 

Well if you multiply the right by 2 you will get rif of the 1/2 BUT if you do it to the right you must do it to the left side as well.

 

\(A=\frac{1}{2}bh\\ A*2=\frac{1}{\not{2}}bh*\not{2}\\ 2A=bh\\ \)

 

Good - Now you want to get rid of the h on the right if you divide by h that will work but divide the other side by h as well!

 

Also the fraction line IS a divide sign   :))

 

\(2A=bh\\ \frac{2A}{h}=\frac{b\not{h}}{\not{h}}\\ \frac{2A}{h}=b\\ \mbox{Now swap sides}\\ b=\frac{2A}{h}\)

 Aug 18, 2016
 #2
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Melody. My silly question.

 

b = 2A / h

What if h is 0 and the triangle is a straight line? b would be infinity for any values of A?

MaxWong  Aug 18, 2016
 #3
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Or am I really worrying so much?

MaxWong  Aug 18, 2016
 #4
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If h is zero, then the area A is zero also, so b would be indeterminate.

 Aug 18, 2016

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