If 1,000 mod n =1, where n=1, 2, 3,4...........998, 999, 1000, just how many n are there between 1 and 1,000? Thank you for help.

Guest Oct 29, 2018

#1**0 **

Here is a bit of computer code that calcultes this kind of question in no time.

a=1000; b=1000; c=(1); n=2; if((a % n)==1,c=(c,n),0); n++; if(n<=b,gotor-2,c);printc; c=sumfor(n, 1, b, (a % n)==1);print"Total =",c

**(3, 9, 27, 37, 111, 333, 999) = 7 Numbers.**

Guest Oct 30, 2018

#2**+8 **

**If 1,000 mod n =1, where n=1, 2, 3,4...........998, 999, 1000, just how many n are there between 1 and 1,000? **

\(\text{Since $1000 \pmod 1 = 0$ and $1000 \pmod {1000} = 0$, $n$ can only be $2,3, \ldots , 999$.} \)

\(\begin{array}{|rcll|} \hline 1000 & \equiv & 1 \pmod n \\ \text{or} \\ 1000-1 &=& n\cdot m,~ \text{with } m \in \mathbb{Z} \\ 999 &=& n\cdot m,~ \text{so $n$ are all divisors of $999$ except $1$ } \\ \hline \end{array} \)

**The divisors of 999 are:**

Divisors:

1 | 3 | 9 | 27 | 37 | 111 | 333 | 999 (8 divisors)

**n = 3 | 9 | 27 | 37 | 111 | 333 | 999 (7 numbers)**

heureka Oct 30, 2018