A LADDER IS PLACED AGAINST THE SIDE OF A HOUSE. THE TOP OF THE LADDER IS 24 FEET ABOVE THE GROUND. THE BASE OF THE LADDER IS 7 FT AWAY FROM THE HOUSE. FIND THE LENGHT OF THE LADDER.
The ladder positioned against the wall forms a right triangle. You are trying to find the length of the ladder, which is the hypontenuse of the triange. 24 ft is a leg length, as well as 7ft. Use the pythagorean theorem to solve this problem. A^2+b^2=C^2
24^2+7^2=C^2 Plug in the given values.
576+49=C^2 Square the pieces.
625=C^2 Combine the squared pieces.
25=C Take the square root of both sides.
The length of the ladder is 25 ft.
THe question is a^2+b^2=c^2 problem. Pythagorean theorem.
a and b are the sides that are touch the right angle and c is the side that doesn't
The house makes a right triangle
The ground from where the latter touches to the grount until you reach the house and up until you reach the top of the ladder form a right angle and thus represent a and b. c is the length of the latter. just plug the numbers in the formula
The ladder positioned against the wall forms a right triangle. You are trying to find the length of the ladder, which is the hypontenuse of the triange. 24 ft is a leg length, as well as 7ft. Use the pythagorean theorem to solve this problem. A^2+b^2=C^2
24^2+7^2=C^2 Plug in the given values.
576+49=C^2 Square the pieces.
625=C^2 Combine the squared pieces.
25=C Take the square root of both sides.
The length of the ladder is 25 ft.
