need answer stuck

Close....OliviaPi  ....!!!!

Take it from this step

4 ( x^2 - 7x + 11)  = 0 divide both sides by 4

x^2 - 7x + 11     subtract 11 from both sides

x^2 - 7x   = -11     complete the square 

x^2 - 7x + 49/4  = -11 + 49/4       factor the left side, simplify the right

(x - 7/2) ^2  =  5/4      take ths square root of both sides

x - 7/2  =  (+/-) sqrt(5)/2     add 7/2 to both sides

x = (+/-)sqrt(5)/2 + 7/2

4x^2-28x+49= 5

First, get the equation equal to zero

4x^2-28x+49-5=5-5

Next, see if you can take a GCF (Greatest Common Factor)

4(x^2-7x+11)=0

We can't factor this, bur we can use the quadratic formula

-b +or- square root (b squared - four (a times c))

7 +or- square root (7^2 - 4(1)(11))

7+or- square root(49-45) 

7+or-square root of 5 is your answer!

Solve for x:
4 x^2-28 x+49 = 5

Divide both sides by 4:
x^2-7 x+49/4 = 5/4

Write the left hand side as a square:
(x-7/2)^2 = 5/4

Take the square root of both sides:
x-7/2 = sqrt(5)/2 or x-7/2 = -sqrt(5)/2

Add 7/2 to both sides:
x = 7/2+sqrt(5)/2 or x-7/2 = -sqrt(5)/2

Add 7/2 to both sides:
Answer: | x = 7/2+sqrt(5)/2                           or x = 7/2-sqrt(5)/2