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hoiuu  Oct 31, 2018
 #1
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\(\frac{10π}{5}= 2π \) so for >10π we start from 0 again.The same and with -10π

So \(-\frac{16π}{5}= -\frac{10π}{5}-\frac{6π}{5}= -2π - \frac{6π}{5} = -\frac{6π}{5} \)

Correct answer is \(-\frac{16π}{5}\)

 

Hope this helps! 

Dimitristhym  Oct 31, 2018
edited by Dimitristhym  Oct 31, 2018

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