+31 Hello I am studying for an EOC test and must leave in around 20 MINUTES!!!!!!!!!!!!!!!!
I have the problem 4ab^4 * 2ba^-4
Any help will be extremely appreciated!!!
Simplify the following:
(4 a b)^4/(2 b a)^4
Multiply each exponent in 2 b a by 4:
(4 a b)^4/2^4 b^4 a^4
2^4 = (2^2)^2:
(4 a b)^4/((2^2)^2 b^4 a^4)
2^2 = 4:
(4 a b)^4/(4^2 b^4 a^4)
4^2 = 16:
(4 a b)^4/(16 b^4 a^4)
Multiply each exponent in 4 a b by 4:
4^4 a^4 b^4/(16 b^4 a^4)
4^4 = (4^2)^2:
((4^2)^2 a^4 b^4)/(16 b^4 a^4)
4^2 = 16:
(16^2 a^4 b^4)/(16 b^4 a^4)
| 1 | 6
× | 1 | 6
| 9 | 6
1 | 6 | 0
2 | 5 | 6:
(256 a^4 b^4)/(16 b^4 a^4)
(256 a^4 b^4)/(16 b^4 a^4) = (b^4 a^4)/(b^4 a^4)×256/16 = 256/16:
256/16
The gcd of 256 and 16 is 16, so 256/16 = (16×16)/(16×1) = 16/16×16 = 16:
Answer: | 16
