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I dont get how 3 is a root: (x-1)^3-2(x-1)^2=0

Guest May 10, 2017
 #1
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+1

                                                                      (x - 1)3 - 2(x -1)2  =  0

Factor out the common term (x - 1)2:         (x - 1)2[ (x - 1) - 2 ]  =  0

Simplify:                                                              (x - 1)2[ x - 3 ]  =  0

So, the roots are 1 (a double root) and 3.

geno3141  May 10, 2017
 #2
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Oh man... Thanks a lot! I was loosing a lot of time in this exercise and I need to go study Biology. How couldnt I see that, this wasnt that hard, thx :)

Guest May 10, 2017

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