+491 θ lies in Quandrant I
cos θ = 5/6
What is the exact value of sin θ in simplified form?
A. -√11/6
B. √11/5
C. √11/6
D. - 5√11 / 11
+36916 In quadrant 1 sin and cos are both POSITIVE
cos^2 + sin^2 = 1
(5/6)^2 + sin^2 = 1
sin^2 = 1- 25/36
sin^2 = 11/36
sin = sqrt(11) / 6 (the positive sq rt of 11/36)
