how many 7-digit numbers can be formed if the first digit cannot be 0 or 9 and if the last digit is greater than or equal to 2 and less than or equal to 3? Repeated digits are allowed
how many 7-digit numbers can be formed if the first digit cannot be 0 or 9 and if the last digit is greater than or equal to 2 and less than or equal to 3? Repeated digits are allowed
Hi answering guest. You have 8 numbers in your answer and there are only 7 digits. But you are certainly on the right track.
The first can be 1,2,3,4,5,6,7 or 8 That is 8 posibilities.
Then next 5 can be ans digit so that is 10 possibilities each.
Thge last one can only be 2 or 3. That is 2 possibilities.
so the answer is
8*10*10*10*10*10*2 = 1 600 000
how many 7-digit numbers can be formed if the first digit cannot be 0 or 9 and if the last digit is greater than or equal to 2 and less than or equal to 3? Repeated digits are allowed
Hi answering guest. You have 8 numbers in your answer and there are only 7 digits. But you are certainly on the right track.
The first can be 1,2,3,4,5,6,7 or 8 That is 8 posibilities.
Then next 5 can be ans digit so that is 10 possibilities each.
Thge last one can only be 2 or 3. That is 2 possibilities.
so the answer is
8*10*10*10*10*10*2 = 1 600 000