Let \(f(x) = \begin{cases} k(x) &\text{if }x>2, \\ 2+(x-2)^2&\text{if }x\leq2. \end{cases}\)Find the function k(x) such that f is its own inverse.
Here is a graph.
Can you work it out from that ?
https://www.desmos.com/calculator/fpruev1hep