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9 to the power of -2\3 help

 Feb 2, 2017
 #1
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0.00411522634

 Feb 2, 2017
 #2
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9^(-2/3)  =

 

(1 / 9)^(2/3)  =

 

[(1 / 9)^2 ] ^(1 / 3)  =

 

(1 / 81) ^(1/3) =

 

(  [1/27] * [1 /3] )^(1/3) =

 

(1 / 27)^(1 / 3)  * (1 / 3)^(1 / 3) =

 

1 / [ ∛27 * ∛3  ]  =

 

1 / [ 3 ∛3 ] 

 

 

cool cool cool

 Feb 2, 2017

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