+0  
 
0
85
2
avatar

nonnegative m, n

 

1/m + 1/n = 2^2/(mn^2)

 Jan 12, 2022
 #1
avatar+675 
0

\(\frac{1}{m} + \frac{1}{n} = \frac{2^2}{(mn^2)}\) whereby m and n are positive integers and \(m \neq 0\) and \(n \neq 0\).

 

So when m and n are positive then \(n(m + n) = 4\).

 

Distribute \(n^2 + nm = 4\).

 

There is only one solution: m = 3 and n = 1.

 Jan 12, 2022
 #2
avatar
0

thanks

 Jan 12, 2022

9 Online Users

avatar