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# nonnegative m, n

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nonnegative m, n

1/m + 1/n = 2^2/(mn^2)

Jan 12, 2022

### 2+0 Answers

#1
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$$\frac{1}{m} + \frac{1}{n} = \frac{2^2}{(mn^2)}$$ whereby m and n are positive integers and $$m \neq 0$$ and $$n \neq 0$$.

So when m and n are positive then $$n(m + n) = 4$$.

Distribute $$n^2 + nm = 4$$.

There is only one solution: m = 3 and n = 1.

Jan 12, 2022
#2
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thanks

Jan 12, 2022