Ok guys, so my teacher just tuned up the difficulty meter a notch. Does anybody know how to explain the steps in solving advanced(or seeming advanced) logrithems? Example: 4log8 u+4log 8 ^v
by the way those 8's are bases
When a number is multiplied to a log, the number can be moved inside the log as an exponent:
4log8u + 4log8v
= log8u4 + log8v4
Logs are add, when numbers have been multiplied, so, going backwards, we can combine the above to get:
= log8u4v4
+66 
