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8/3-(sqrt(6))

 Jul 22, 2017
edited by Guest  Jul 22, 2017
 #1
avatar+99388 
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8/3-(sqrt(6))

 

I assume you mean

 

8/[3-sqrt(6)]

 

you have to multiply by the conjugate of the denominator.

 

\(\frac{8}{3-\sqrt6}\\ =\frac{8}{3-\sqrt6}\times \frac{3+\sqrt6}{3+\sqrt6}\\ =\frac{8(3+\sqrt6)}{9-6}\\ =\frac{24+8\sqrt6}{3}\\\)

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 Jul 22, 2017
 #2
avatar+1900 
0

I assume you mean \(\frac{8}{3}-\sqrt{6}\)

 

\(\frac{8}{3}-\sqrt{6}\)

 

\(\frac{8}{3}-\frac{3\sqrt{6}}{3}\)

 

Exact answer:

 

\(\frac{8-3\times\sqrt{6}}{3}\)

 

Approximate answer:

 

\(\frac{8-3\times\sqrt{6}}{3}\)

 

\(\frac{8-3\times2.4494897427831781}{3}\)

 

\(\frac{8-7.3484692283495343}{3}\)

 

\(\frac{0.6515307716504657}{3}\)

 

\(0.2171769238834885667\)

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 Jul 23, 2017

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