Operations on Radical Expressions

8/3-(sqrt(6))

I assume you mean

8/[3-sqrt(6)]

you have to multiply by the conjugate of the denominator.

$\frac{8}{3-\sqrt6}\\ =\frac{8}{3-\sqrt6}\times \frac{3+\sqrt6}{3+\sqrt6}\\ =\frac{8(3+\sqrt6)}{9-6}\\ =\frac{24+8\sqrt6}{3}\\$

I assume you mean $\frac{8}{3}-\sqrt{6}$

$\frac{8}{3}-\sqrt{6}$

$\frac{8}{3}-\frac{3\sqrt{6}}{3}$

Exact answer:

$\frac{8-3\times\sqrt{6}}{3}$

Approximate answer:

$\frac{8-3\times\sqrt{6}}{3}$

$\frac{8-3\times2.4494897427831781}{3}$

$\frac{8-7.3484692283495343}{3}$

$\frac{0.6515307716504657}{3}$

$0.2171769238834885667$