If you had 12 possible outcomes what are the odds that each outcome would come up exactly 3 times out of 36 drawings? So I'm going to make a random drawing 36 times and the outcome can be numbers 1-12. What are the odds, that each number would come out exactly 3 times? (note each number is NOT removed after being drawn, it is put back in so there are always 12 possible outcomes (#'s 1-12) I would assume that it is 12 (# of outcomes) x 36 (number of drawings) = 432 Then divide this by 3 (times each number coming up) 432 / 3 = 144 So 1 in 144 times? Although, I feel this is way off. Perhaps it is 12 to the 36th power?
