Paige invested $1,200 at an interest rate of 5.75% compounded quarterly. Determine the value of her investment in 7 years.
(I have seen answers a bit like the first one before. Parts of it are probably correct)
This is how I do it.
interest rate is 5.75%per annum (I am assuming)
this is 5.75% /4 = 1.4375% per quarter = 0.014375
7 years = 7*4 = 28 quarters.
$${\mathtt{A}} = {\mathtt{1\,200}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.014\: \!375}}\right)}^{{\mathtt{28}}} \Rightarrow {\mathtt{A}} = {\mathtt{1\,789.535\: \!370\: \!887\: \!419\: \!769\: \!3}}$$
The value will be $1789.54 to the nearest cent.
Use the formula A(t)=Pe^rt
A(t) is the final amt.; which is what you are trying find. P is the initial investment (1,200). e is the natural base, which will always have an exponent. e can be found on a calculator. In this case, R is the rate, which needs to be turned into a decimal (5.75% to 0.0575). t is time (7 years). So your equation should look like this:
A(t)= 1,200e^0.0575(8)
Solve and you should get your answer.
(I have seen answers a bit like the first one before. Parts of it are probably correct)
This is how I do it.
interest rate is 5.75%per annum (I am assuming)
this is 5.75% /4 = 1.4375% per quarter = 0.014375
7 years = 7*4 = 28 quarters.
$${\mathtt{A}} = {\mathtt{1\,200}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.014\: \!375}}\right)}^{{\mathtt{28}}} \Rightarrow {\mathtt{A}} = {\mathtt{1\,789.535\: \!370\: \!887\: \!419\: \!769\: \!3}}$$
The value will be $1789.54 to the nearest cent.