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Paige invested $1,200 at an interest rate of 5.75% compounded quarterly. Determine the value of her investment in 7 years.

 May 6, 2014

Best Answer 

 #3
avatar+118724 
+5

(I have seen answers a bit like the first one before.  Parts of it are probably correct)

This is how I do it.

interest rate is 5.75%per annum (I am assuming)

this is 5.75% /4 = 1.4375% per  quarter = 0.014375

7 years = 7*4 = 28 quarters.

$${\mathtt{A}} = {\mathtt{1\,200}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.014\: \!375}}\right)}^{{\mathtt{28}}} \Rightarrow {\mathtt{A}} = {\mathtt{1\,789.535\: \!370\: \!887\: \!419\: \!769\: \!3}}$$

The value will be $1789.54 to the nearest cent.     

 May 6, 2014
 #1
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Use the formula A(t)=Pe^rt

A(t) is the final amt.; which is what you are trying find. P is the initial investment (1,200). e is the natural base, which will always have an exponent. e can be found on a calculator. In this case, R is the rate, which needs to be turned into a decimal (5.75% to 0.0575). t is time (7 years). So your equation should look like this: 

A(t)= 1,200e^0.0575(8)

Solve and you should get your answer.

 May 6, 2014
 #2
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Correction to my previous statement, 7 should be in the parenthesis as the time.

 May 6, 2014
 #3
avatar+118724 
+5
Best Answer

(I have seen answers a bit like the first one before.  Parts of it are probably correct)

This is how I do it.

interest rate is 5.75%per annum (I am assuming)

this is 5.75% /4 = 1.4375% per  quarter = 0.014375

7 years = 7*4 = 28 quarters.

$${\mathtt{A}} = {\mathtt{1\,200}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.014\: \!375}}\right)}^{{\mathtt{28}}} \Rightarrow {\mathtt{A}} = {\mathtt{1\,789.535\: \!370\: \!887\: \!419\: \!769\: \!3}}$$

The value will be $1789.54 to the nearest cent.     

Melody May 6, 2014

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