The x-intercepts of the parabola y=x^2+bx are (-3,0) and \((6,0)\) Find the equation of the parabola, and submit your answer in y=ax^2+bx+c form.

Guest May 23, 2022

#1**0 **

We know the quadratic is in the form \(y = x^2 + bx + c\)

Substituting the 2 points we know, we have: \(0 = 9 - 3b + c\) and \(0 = 36 + 6b + c \)

Now, we have to solve for b and c, and substitute them back into the form of the quadratic.

Can you take it from here?

BuilderBoi May 23, 2022