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The x-intercepts of the parabola y=x^2+bx are (-3,0) and \((6,0)\) Find the equation of the parabola, and submit your answer in y=ax^2+bx+c form.

 May 23, 2022
 #1
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We know the quadratic is in the form \(y = x^2 + bx + c\)

 

Substituting the 2 points we know, we have: \(0 = 9 - 3b + c\) and \(0 = 36 + 6b + c \)

 

Now, we have to solve for b and c, and substitute them back into the form of the quadratic. 

 

Can you take it from here?

 May 23, 2022

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