Permutation times Combination

What is 8P1 * 5C3?=[8!/(8-1)!] x [5!/(5-3)! 3!]=8 x 10=80

_nP_r  =  n! / (n - r)!     --->     ₈P₁  =  8! / (8 - 1)!  =  8! / 7!  =  8

_nC_r  =  n! / [ (n - r)! · r! ]    --->     ₅C₃  =  5! / [ (5 - 3)! · 3! ]  =  5! / [ 2! · 3! ]  =  10

So the answer is  8 x 10  =  80