Perpendicular problem

Write the slope-intercept form of the equation of the line described.

A line through (-4,0) Perpendicular to y=x-1

The slope-intercept form of a line is y = mx + b, where m represents the slope and b represents the y-intercept.

The equation y=x-1 shows that the slope of the line m is 1.

The line perpendicular has the slope \(m_{\text{perpendicular}} = -\frac{1} {m} = -\frac{1}{1} = -1\)

The line through (-4,0) is  \(0 = (-1)\cdot (-4)+b\)

so  \(b=-4\)

The slope-intercept form of the equation of the line is  \(\mathbf{y = -x - 4}\)

 I can't help, but good luck! You should make an account if you have an account your questions (according to Melody) are made top priority.:)

How did you get to the b=-4 because -1*-4 should equal 4 right?

A line perpendicular to the given one will have a slope of  -1.......so........using point-slope form, we have

y - 0 = -1 [ x - (-4)]   =

y = -1 [x + 4]  =

y  = -x - 4     and that's in slope - intercept form    .......just as heureka found........