physics please help

if m is doubled then

$$t=e^{-2aL}$$

would still be written the same way!  However, 'a' would be different.  So if we use 'a' for the original and 'a₂' for  when m is doubled then we could write:

$$t=e^{-2a_2L}$$

or

$$t=e^{-2\sqrt2aL}$$

.

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Melody, hbar is Planck's constant h divided by 2pi and is usually written with the bar crossing the upright of the h rather than being above the h, thus:   $$\hbar$$

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Thanks Alan :)