Two astronauts of mass 100 kg are 2 m apart in outer space. What is the force of gravity between them? (G = 6.67 10-11 N•m2/kg2)
+101 Let m1 = m2 = m ( the mass of the astronaut )
the force F is equal to (G*m1*m2)/d² where d is the distance between the two astronauts
\(f=\frac{G{m}_{1}{m}_{2}}{d²}\)
\(f=\frac{Gm²}{d²}\)
\(f=\frac{6.67*{10}^{-11}*{10}^{4}}{4} = 1.6675*{10}^{-7} N\)
that means there is an attracted force between any two material objects.
This force is proportionally inversed with the square of the distance separating the two objects
according to the result, this force isn't noticibale (1.6675*10^7 is practically 0), that's why we can't feel it
+101 Let m1 = m2 = m ( the mass of the astronaut )
the force F is equal to (G*m1*m2)/d² where d is the distance between the two astronauts
\(f=\frac{G{m}_{1}{m}_{2}}{d²}\)
\(f=\frac{Gm²}{d²}\)
\(f=\frac{6.67*{10}^{-11}*{10}^{4}}{4} = 1.6675*{10}^{-7} N\)
that means there is an attracted force between any two material objects.
This force is proportionally inversed with the square of the distance separating the two objects
according to the result, this force isn't noticibale (1.6675*10^7 is practically 0), that's why we can't feel it
