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A weather balloon is launched from sea level (pressure = 1atm). It initially has a volume of 1.3 m3 with 25°C ideal helium inside of it. It rises in the earth's atmosphere, cooling and expanding in volume. What will be its new volume if its final temperature and pressure are -43°C and 0.15 atm?

 

A.8.1 m3 

B.4.2 m3 

C.6.7 m3 

D.2.3 m3

 Jun 2, 2016
 #1
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Using pressure/volume/temperature laws for IDEAL gasses:

 

p1 v1 / t1   =   p2 v2 / t2      where t is in KELVIN degrees

 

(1)(1.3) / (25+273.15)  =  (.15) v2 / (-43 + 273.15)

 

solve for v2 = 6.69 m^3

 Jun 2, 2016
 #2
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C

 

T is temperature in Kelvin

273 Kelvin = 0 C

P1*V1/T1 = P2*V2/T2

(Pressure 1 * Volume 1 / Temperature 1 in Kelvin = Pressure 2 * Volume 2 / Temperature 2 in Kelvin)

1*1.3 = 1.3

1.3/(273+25) = 0.00436

 

0.00436 = (0.15*v)/(273-43)

0.15*v/230 = 6.68

 

Round up 6.68 to 6.7

 Jun 2, 2016
 #3
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Looks like your balloon is at C.

 Jun 2, 2016

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