please help 7 th grade math

21 1/3 times 11 1/3 times 3 5/8..........let's convert these to improper fractions, first

21 + 1/3  =  64/3

11 + 1/3  =  32/3

3 + 5/8   =   29/8   ....and we have....

(64 / 3) * (34 / 3)  * ( 29/8)     multiply the numerators together and the denominators together

63,104 / 72      divide by 2

31,552 / 36     again

15,776 / 18     again

7888 / 9

And that's all we can do.....

Simplify the following:
(21+1/3) (11+1/3) (3+5/8)

Put 3+5/8 over the common denominator 8. 3+5/8  =  (8×3)/8+5/8:
(21+1/3) (11+1/3) (8×3)/8+5/8

8×3  =  24:
(21+1/3) (11+1/3) (24/8+5/8)

24/8+5/8  =  (24+5)/8:
(21+1/3) (11+1/3) (24+5)/8

24+5 = 29:
(21+1/3) (11+1/3)×29/8

Put 11+1/3 over the common denominator 3. 11+1/3  =  (3×11)/3+1/3:
((21+1/3) (3×11)/3+1/3 29)/(8)

3×11  =  33:
((21+1/3) (33/3+1/3)×29)/(8)

33/3+1/3  =  (33+1)/3:
((21+1/3) (33+1)/3×29)/(8)

33+1 = 34:
((21+1/3)×34/3×29)/(8)

Put 21+1/3 over the common denominator 3. 21+1/3  =  (3×21)/3+1/3:
((3×21)/3+1/3 34×29)/(3×8)

3×21  =  63:
((63/3+1/3)×34×29)/(3×8)

63/3+1/3  =  (63+1)/3:
((63+1)/3×34×29)/(3×8)

63+1 = 64:
64/3×34/3×29/8

64/3×34/3×29/8 = (64×34×29)/(3×3×8):
(64×34×29)/(3×3×8)

64/8 = (8×8)/8 = 8:
(8×34×29)/(3×3)

3×3  =  9:
(8×34×29)/9

8×34  =  272:
(272×29)/9

| 2 | 7 | 2
× |  | 2 | 9
2 | 4 | 4 | 8
5 | 4 | 4 | 0
7 | 8 | 8 | 8:
Answer: | 
| 7888/9=876 4/9

Huh?  Why don't you change it back to a mixed numeral Chris ?

Doesn't matter....I apparently can't multiply correctly, anyway.....LOL!!!!!