ABCD is a quadrilateral such that AB=CD. We know that angleA= angle B= 60 degrees and AD=CB=1 . If AB=10 , what is DC?
ABCD is a quadrilateral such that AB\(\parallel\)CD. We know that angleA= angle B= 60 degrees and AD=CB=1 . If AB=10 , what is DC?
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\(\overline{DC}=\overline{AB}-2\cdot (1\cdot cos\ 60^{\circ})=10-2\cdot 0.5\)
\(\overline{DC}=9\)
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