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Let T be a point inside square EFGH such that TE = sqrt6, TF = 2sqrt3, and TG = 3sqrt2. Find angle ETF.

 Oct 21, 2021
 #1
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Using trig, I got that angle ETF = 125 degrees.

 Oct 21, 2021
 #2
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Angle ETF = 105 degrees

 

EF = 3 + √3

 

Angle FTG = 75 degrees

 

Line segment EG is a diagonal of square EFGH.

 

(Don't ask me how I've done it.) laugh

 Oct 22, 2021
edited by Guest  Oct 22, 2021
edited by civonamzuk  Oct 22, 2021

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