Let T be a point inside square EFGH such that TE = sqrt6, TF = 2sqrt3, and TG = 3sqrt2. Find angle ETF.
Using trig, I got that angle ETF = 125 degrees.
Angle ETF = 105 degrees
EF = 3 + √3
Angle FTG = 75 degrees
Line segment EG is a diagonal of square EFGH.
(Don't ask me how I've done it.)
+1694 
