Using L'Hopital's Rule, Find $Lim_{x\to\infty} \frac{3x^3}{x^2}$
We need to use it twice [ derivative of numerator / derivative of denominator ]
First time we get [ 9x^2] / [ 2x]
Second time we get [ 18x ] / 2 = 9x
So
lim 9x = inf [ so....the limit doesn't exist ]
x → inf
