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in a clinical study , volunteers are tested for a gene that has been found to increase the risk for a disease the probability that a person carries the gene is 0.2 
1) what is the probablilty that 8 or more people will have to be tested before 3 with the gene are detected 
2) how many people are expected to be tested before 3 ith gene are detected 

 May 29, 2018
 #1
avatar+109738 
+3

in a clinical study , volunteers are tested for a gene that has been found to increase the risk for a disease the probability that a person carries the gene is 0.2 

p=0.2     q=0.8


1) what is the probablilty that 8 or more people will have to be tested before 3 with the gene are detected 

 

   P(8 or more need to be tested before 3 are detected)

=P(2 or less will have it if 7 people are tested)

=P(0 out 7 have it) + P(1 out 7 have it) + P(2 out 7 have it)

\(=  7C0 * 0.8^7 + 7C1 * 0.2*0.8^6 +7C2 * 0.2^2 * 0.8^5\\ = 0.8^7 + 7* 0.2*0.8^6 +21 * 0.04 * 0.8^5\\\)

0.8^7 + 7* 0.2*0.8^6 +21 * 0.04 * 0.8^5 = 0.851968

 

approx 85.2%

 


2) ??

 May 29, 2018
 #2
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0

This is not the right answer. It’s not even close.

I have the correct answer but I don’t know how to do the workings.

 Jun 3, 2018
 #3
avatar+109738 
+1

You have not even said what you think the answer is. 

Perhaps your are reading the answer section of your book upside down?

 

 

I stand by the answer that I have provided.

but if someone can see a flaw in my logic I will certainly listen to their reasoning. 

 Jun 3, 2018
 #4
avatar+2420 
0

I think I can answer the second one.

 

2) Well, if the probability of the of someone carrying this particular is 0.2, then the reciprocal would represent the number of times I would expect before I hit a match. Since 3 people need to be detected, multiply this by three.

 

 \(3*\frac{1}{0.2}=15\text{ people}\)

 


 

TheXSquaredFactor  Jun 3, 2018
 #5
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0

It’s not what I think the answer is. It’s not a book, it’s an online homework practice site. If you enter a wrong answer in the box it gives the correct answer, but it doesn’t show how to get it. 

 Jun 3, 2018
 #6
avatar+2420 
0

Is the answer around 66%? 

TheXSquaredFactor  Jun 5, 2018

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