\(\text{There's no way that }q(x) \text{ can cancel any terms higher than degree }7\\ \text{Thus the sum will still be of degree }11 \text{ given all }q(x)\)
\(\text{There's no way that }q(x) \text{ can cancel any terms higher than degree }7\\ \text{Thus the sum will still be of degree }11 \text{ given all }q(x)\)
+150 
