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I am learning about quadratics. I am trying to find the x-intercepts.I can't seem to solve x2-9x+24=0 I feel like I am missing something. Both of my points will have to be negative in order for me to have a positive 24.

 Dec 2, 2015
 #1
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x^2 - 9x + 24 = 0  

 

This has no x intercepts.....the discrminant =  b^2 - 4ac =  (-9)^2  - 4(1)(24)   =  81 - 96   = - 15

 

Anytime the discriminant < 0.......we won't have any real roots [ x intercepts]

 

Here's a graph to help you......https://www.desmos.com/calculator/esjonexqaa

 

 

cool cool cool

 Dec 2, 2015

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