+612 Points $A$ and $B$ have the same $y$-coordinate of 13, but different $x$-coordinates. What is the sum of the slope and the $y$-intercept of the line containing both points?
+9479 Let point A be (a, 13)
Let point B be (b, 13)
slope between point A and point B \(=\,\frac{\text{difference in y-coordinates}}{\text{difference in x-coordinates}}\\~\\ =\,\frac{13-13}{a-b}\\~\\ =\,\frac{0}{a-b}\\~\\ =\,0\)
Line AB is a horizontal line where the y-coordinate of all its points is 13 .
So the y-coordinate when x = 0 is also 13 .
y-intercept = 13
sum of slope and y-intercept = 0 + 13 = 13
+9479 Let point A be (a, 13)
Let point B be (b, 13)
slope between point A and point B \(=\,\frac{\text{difference in y-coordinates}}{\text{difference in x-coordinates}}\\~\\ =\,\frac{13-13}{a-b}\\~\\ =\,\frac{0}{a-b}\\~\\ =\,0\)
Line AB is a horizontal line where the y-coordinate of all its points is 13 .
So the y-coordinate when x = 0 is also 13 .
y-intercept = 13
sum of slope and y-intercept = 0 + 13 = 13
