Points $A$ and $B$ have the same $y$-coordinate of 13, but different $x$-coordinates. What is the sum of the slope and the $y$-intercept of the line containing both points?

gueesstt Apr 16, 2018

#1**+2 **

Let point A be (a, 13)

Let point B be (b, 13)

slope between point A and point B \(=\,\frac{\text{difference in y-coordinates}}{\text{difference in x-coordinates}}\\~\\ =\,\frac{13-13}{a-b}\\~\\ =\,\frac{0}{a-b}\\~\\ =\,0\)

Line AB is a horizontal line where the y-coordinate of all its points is 13 .

So the y-coordinate when x = 0 is also 13 .

y-intercept = 13

sum of slope and y-intercept = 0 + 13 = 13

hectictar Apr 16, 2018

#1**+2 **

Best Answer

Let point A be (a, 13)

Let point B be (b, 13)

slope between point A and point B \(=\,\frac{\text{difference in y-coordinates}}{\text{difference in x-coordinates}}\\~\\ =\,\frac{13-13}{a-b}\\~\\ =\,\frac{0}{a-b}\\~\\ =\,0\)

Line AB is a horizontal line where the y-coordinate of all its points is 13 .

So the y-coordinate when x = 0 is also 13 .

y-intercept = 13

sum of slope and y-intercept = 0 + 13 = 13

hectictar Apr 16, 2018