A particular right pyramid has a square base, and each edge of the pyramid is four inches long. What is the volume of the pyramid?
+47 Volume of a pyramid:
\(V = {area{*height} \over 3}\frac{}{}\)
Area of base = 16 inches
Height =
\(h =\sqrt{4^2- ({(\sqrt{16+16}) \over 2})^2}{}_{}\)
\(h= {\sqrt{8}}\)
Final formula:
\(V= {1\over 3}* 16 * \sqrt{8}\)
\(V = 15.0849446653\)
\(V = 15.08\)
Volume = 15.08
