What is the quotient of the complex number \(4-3i\) divided by its conjugate?

Guest May 1, 2021

#3**+2 **

Thanks Catmg, some working might be helpful

\(\frac{4-3i}{4+3i}\\ =\frac{4-3i}{4+3i}\times \frac{4-3i}{4-3i}\\ =\frac{16-9-24i}{16+9}\\ =\frac{7-24i}{25}\\ \)

Melody May 1, 2021

#5**0 **

The answer wasn't what cat said? I've been trying to use latex to write my answers down but I can't figure it out.

Guest May 1, 2021

#7**+2 **

Thank you catmg and Melody!!! I'm glad you guys actually show me how to get the answer. Some people just write the answer and don't explain it.

Guest May 1, 2021

#8**+1 **

You're welcome. :))

Glad you understand.

Remember that conjugate is just the negative of the imaginary part, so a + bi turns into a - bi.

=^._.^=

catmg
May 1, 2021

#13**0 **

If you want more explantion, always ask for it.

I mean you can say, "Thanks for the answer but can you show me how you got that please"

I like it when people ask me questions related to my answer.

It means I actually have an audience and someone at the other end is actually trying to learn from me.

Melody
May 1, 2021