The semicircle below has diameter . Find the area of the blue region.
You can type "pi" in place of in your answer as needed.
+505 Fun question :)
Find the area of the semicircle first!
\(\frac{(\pi10^2)}{2}=50\pi \)
Then the area of the triangle.
\(\frac{16*12}{2}=96\).
Answer.
\(50\pi - 96\)
At least I think
