Adam has 3 times as many red stamps as Xion and 6 blue stamps. Cindy
had \({1 \over 6}\)the number of red stamps that Adam has and 3 blue stamps. Cindy has
4 stamps fewer than Xion.
(a) How many stamps do they have altogether?
(b) How many stamps must Adam give to Xion so that they will have the same
number of stamps?
Let Xion has x red stamps.
Adam has 3 times as many red stamps.
Adam has 3x red stamps.
Again Adam has 6 blue stamps
=) Total no. of stamps Adam = 3x + 6.
Condy has 1/6 the number of red stamps Adam has.
=> Cindy has 1/6 * 3x = 1/2x red stamps.
Cindy has x/2 red stamps.
Again Cindy has 3 blue stamps.
=) Total no. of stamps Cindy has = x/2 + 3.
Given, that Cindy has 4 stamps fewer than Xion.
=> x/2 + 3 = x - 4.
=) x/2 - x = -4 - 3
=) - x/2 = -7
=) x = 14
Xion has 14 stamps.
Adam has 3 * 14 + 6 = 48 stamps
Adam has 48 stamps.
Cindy has x/2 + 3 = 14/2 + 3 = 10 stamps.
Cindy has 10 stamps.
(a)Total no. of stamps they have altogether = 14 + 48 + 10 = 72
They have altogether 72 stamps.
(b)New Xion has 14 stamps and Adam has 48 stamps
Let Adam gives y stamps to Xion so that they will
have some stamps.
=> 48 - y = 14 + y
=> 48 - 14 = 2y =)2y = 3y =) y = 17
Adam must give 17 stamps to Xion so that they'll have
same no. of stamps.
