farhan cycles the first part of a 150 km journey at an average speed of 35km/h. If he takes 4.5 hours for his entire journey, find the distance that he cycles.
+118608 There is not enough info given here. :(
I am jsut playing ....
farhan cycles the first part of a 150 km journey at an average speed of 35km/h.
x km at 35km/hour that is
\(\frac{x}{35} hours\)
If he takes 4.5 hours for his entire journey, find the distance that he cycles.
(150 - x) km left
\(4.5 - \frac{x}{35} =\frac{ (4.5*35-x)}{35} = \frac{157.5-x}{35}\;\;hours\;\;left\)
\((150-x)\div \frac{157.5-x}{35}\;\;km/hour\\ \frac{35(150-x)}{157.5-x}\;\;km/hour\\\)
Your question isn't very clear!. However, if we assume that Farhan covered the first 150 km at an average of 35 km/h, then it took too him: 150/35 =4 2/7 hours to cover that distance.
But the total distance was covered in 4 1/2 hours. Therefore, it took him: 4.5 - 4 2/7 =3/14 of an hour to cover the remaining distance. And since his average speed was 35 km/h for the first 150 km, will assume that the averge speed for the remaining distance was also 35 km/h. Therefore, the remaining distance would be: 35 km/h x 3/14 =7.50 km. So, the total distance cycled would be: 150 + 7.5 =157.5 km.
