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Suppose $\frac{1}{2} + \frac{1}{3} + \ldots +\frac{1}{x} > 1\frac{1}{2}$ What is the smallest possible value for $x$ ?

YeetusBoy10 Sep 22, 2020

Guest · Answer 1 · 2020-10-04T04:20:54

The smallest possible value of x is 12.