make s the subject of formuale of
t^2=2p+as
Solve for s: t2 = 2p + as
Rewrtie: 2p + as = t2
subtract as from both sides: 2p = t2 - as
divide by 2: p = ( t2 - as ) / 2
geno3141: Don't you want to solve for s?
Solve for s: t^2 = 2 p + a s
t^2 = 2 p + a s is equivalent to 2 p + a s = t^2: 2 p + a s = t^2
Subtract 2 p from both sides: a s = t^2 - 2 p
Divide both sides by a: s = t^2/a - (2 p)/a
