+1491 You are given:
3 \(\sqrt{27}\)
Let's ignore the three for now. So you have:
\(\sqrt{27}\)
Now we can separate the multiples of 27 INSIDE the square root and see if any are perfect squares:
\(\sqrt{9 * 3}\)
Nine is a perfect square and if you square nine you get three, put that three on the outside:
3 \(\sqrt{3}\)
Dont forget to multiply the three back in!
9\(\sqrt{3}\)
