The x-intercetps of the parabola y = 2x^2 + 13x - 4\(+ 2x^2 - 6x + 5\) are at (p,0) and (q,0). Find p and q. Enter your answer in the form "p,q".
Find p and q.
\( y = 2x^2 + 13x - 4+ 2x^2 - 6x + 5\\ y=4x^2+7x+1\\ y=x^2+1.75x+0.25=0 \)