All triangles have the same value, and all circles have the same value. What is the sum of two circles?
\(\begin{align*} \Delta + \bigcirc + \Delta + \bigcirc + \bigcirc + \Delta + \Delta&= 21\\ \bigcirc + \Delta+\bigcirc+\Delta+\bigcirc + \Delta + \bigcirc &= 16\\ \bigcirc + \bigcirc &= \ \, ? \end{align*}\)
+579 Hello
So we will say that the triangle = x and the circle = y
We get the following equations
\(4x+3y=21,\:3x+4y=16\)
\(\mathrm{Substitute\:}x=\frac{21-3y}{4}\)
\(\begin{bmatrix}3\cdot \frac{21-3y}{4}+4y=16\end{bmatrix}\)
\(\begin{bmatrix}\frac{63+7y}{4}=16\end{bmatrix}\)
\(y=1/7\)
That's all we need to solve the rest!!!
\(y+y=? \)
\(1/7+1/7 = 2/7\)
-Vinculum
