how do i find the zeros of x^3-7x+6
This factorises nicely as: (x - 1)(x - 2)( x+ 3)
(x - 1)(x - 2)( x+ 3) → (x^2 - 3x + 2)(x + 3) → x^3 + 3x^2 - 3x^2 - 9x + 2x + 6 → x^3 - 7x + 6
