Poster is to be designed with 50 in2 of printed type, 4 inch margins on both the top and the bottom, and 2 inch margins on each side. Find the dimensions of the poster which minimize the amount of paper used.
printed area = 50 = xy paper size, P(x) = (x + 2*2)(y + 2*4) =(x + 4)(y + 8) = xy + 4y + 8x + 32 = 8x + 4(50/x) + (50 + 32) = 8x + 200/x + 82 P'(x) = 8 - 200/x^2 = 0 x = √(200/8) = 5 (for x > 0) answer : paper dimension = 9 x 18
:)
Have a wonderful day!!
Very impressive Hayley.
I didn't know you could answer questions that are this advanced !
The only thing I would suggest is that you show this is a minimum (unless you give a reason, it could be a maximum!)
