what is the result of multiplying the following complex number (2+3i)(3-2i)
(2+3i)(3-2i) =
2*3 + 3*3i - 2*2i - 3i * 2i =
6 + 9i - 4i - 6i2 =
6 + 5i - 6(-1) =
6 + 5i + 6 =
12 + 5i
Oh.. I have not takin Pre-Calc .. I cannot help you :(
I'm sorry
so, that's how you do it!
