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There are 22 sets of b***s numbered 11 through 1313 placed in a bowl. If 22 b***s are randomly chosen without replacement, find the probability that the b***s have the same number. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Guest Mar 11, 2017
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We have   22 [1313  - 11 + 1]   = 28666 b***s

 

And we have 1313  - 11 + 1  = 1303 different possibilities for the 1st ball

 

So....the probability that the next 21 b***s we draw out match this number =

 

 21! /[  28665! / 28644!]  

 

So....the total probability =

 

Ways to choose the 1st ball x probability of matching the 1st ball =

 

1303 * 21! * 28644! / 28665! =

 

                                            1303

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78138407065870996272303703695459299504064656359530399953320901718968820150

 

In other words.......highly improbable !!!!

 

 

cool cool cool

CPhill  Mar 12, 2017

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