If three, standard, 6-faced dice are rolled, what is the probability that the sum of the face up integers is 17?
There are 6×6×6=216 possibilities.
The only way to get a sum of 17 is to have a 6, 6, and 5, which can be done in 3!÷2=3 ways (divide by 2 because there are 2 6's)
So, the probability is 3216=172