If three, standard, 6-faced dice are rolled, what is the probability that the sum of the face up integers is 17?
+2666 There are \(6 \times 6 \times 6 = 216\) possibilities.
The only way to get a sum of 17 is to have a 6, 6, and 5, which can be done in \(3! \div 2 = 3\) ways (divide by 2 because there are 2 6's)
So, the probability is \({3 \over 216} = \color{brown}\boxed{{1 \over 72}}\)
