+0  
 
+11
1779
1
avatar+884 

Four consecutive positive prime numbers have a sum that is divisible by three. What is the smallest possible value of this sum?

 Feb 27, 2017
 #1
avatar
+3

5 + 7 + 11 + 13 =36/3 =12

 Feb 27, 2017

1 Online Users

avatar