A cannonball is fired on flat ground at 420 m/s at a 53.0 degree angle. What maximum height does it reach?
X: 420cos53.0 = 252
Y: 420sin53.0 = 335
X
Vi=252
a=0 (because gravity is only along the Y axis)
Y
Vi=335
a=(-9.80) (because of gravity)
Vf=0 (because when at the highest point, there is no Y velocity)
Use Y numbers to figure the maximum height.
The way I've tried is with the equation Vf^2=Vi^2+2a(deltaY), which when rearranged to get deltaY (which is what we're looking for) is -Vi^2/2a = (deltaY) but it gives me an outrageous number that is incorrect.
Do I need to find time in order to find the answer to this question or what? I'm confused. Please help me to solve this.
