Points A, B, C, and T are in space such that each of \($\overline{TA}$\), \($\overline{TB}$\), and \($\overline{TC}$\) is perpendicular to the other two. If $TA = TB = 12$ and $TC = 6$, then what is the distance from $T$ to face $ABC$?
The distance from T to face ABC is 3*sqrt(5).
+28 
