Pythagorean Thereom
so lets say 12=a and 13=c well then uaing the Pythagorean Thereom which is int his case a^2+b^2=c^2
so if with plug in our numbers 12^2+b^2=13^2 so we simplify 144+b^2=169 so we get rid of 144 from both sides to get rid of that 144 b^2=25 and we take the sqrt() of each side or square root because that is the oposite of exponents and we get b= sqrt(25) and the sqrt(25) is 5 so b=5 so it is 5
The Pythagorean Theorem is as follows:
a²(first side) + b²(second side) = c²(hypotenuse)
So, if you're looking for b, then we can put a = 12 & c = 13
12² + b² = 13² <=> b² = 13² - 12² = 25
Now take the primary square root of b², you get the square root of 25, which is 5.
Pythagorean Thereom
so lets say 12=a and 13=c well then uaing the Pythagorean Thereom which is int his case a^2+b^2=c^2
so if with plug in our numbers 12^2+b^2=13^2 so we simplify 144+b^2=169 so we get rid of 144 from both sides to get rid of that 144 b^2=25 and we take the sqrt() of each side or square root because that is the oposite of exponents and we get b= sqrt(25) and the sqrt(25) is 5 so b=5 so it is 5